Question

Let g(x) = 3x+2 and f(x) = (x-2) /3. Find the value.g(f(2))a) 1b) 0c) 2d) 1/3

Answer 1

Given that,

g(x)=3x+2

and f(x)=(x-2)/3

To find,

`g(f(2))`

we get that,

`f(2)=(2-2)/(3)`
`=0`

Substituting this we get,

`g(f(2))=g(0)`
`g(0)=3(0)+2`
`g(0)=2`

Hence, we get

`g(f(2))=2`

Answer is: option (c): 2