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3 votes
A number, x, is 4 times another number, y. The difference

between the two numbers is 18. What is the value of the
larger number?

User Karbi
by
4.3k points

2 Answers

9 votes

Final answer:

The larger number is 24.

Step-by-step explanation:

In this problem, we have two numbers, x and y. It is given that x is 4 times y, and the difference between the two numbers is 18. Let's define the equations based on the given information:

x = 4y

x - y = 18

We can substitute the value of x in the second equation:

4y - y = 18

Simplifying, we get:

3y = 18

Dividing both sides by 3, we find:

y = 6

Now, substituting the value of y in the equation x = 4y, we can find the value of x:

x = 4(6)

x = 24

Therefore, the value of the larger number is 24.

User Cthos
by
4.7k points
10 votes

Answer:

The value of the larger number is


x=24

Step-by-step explanation:

A number, x, is 4 times another number, y.


x=4y --------- (1)

The difference between the two numbers is 18.


x-y=18 -------(2)

Re-arranging equation (2) yields


-y=18-x\\y=x-18------------- (3)

Substitute y=x-18 in equation (1)


x=4 (x-18)


x=4x-72\\x-4x=-72


-3x=-72\\x=(72)/(3)\\x=24

Substitute x=24 in equation (3)


y=24-18\\y=6

User Andre Mikulec
by
4.7k points