Question

A.) What is the exact surface area of the container with a radius of 9 in and a height of 36 in?

Answer 1

it could be a cylinder

I will put the SA formula for btoh

SAcylinder=2pir^2+2hpir
2pir^2=2 bases
2hpir=around area

r=9
h=36
SA=2pi9^2+2*36pi*9
SA=2pi81+72pi9
SA=162pi+648pi
SA=810pi

aprox pi=3.141592

SA=2544.68952 in^2

Answer 2

r = 9
h = 36
Pp = ?area of ​​a circle
l = ? surface of the wheel
Pb = lateral surface
Pc - total surface

Pp = πr² = 9²*π = 81π (unit²)
l = 2πr = 2*9*π = 18π (unit)
Pb = l*h = 18π * 36 = 648 π(unit²)
Pc = 2Pp + Pb = 2* 81π + 648π = 162π + 648π = 810π(unit²)

Answer total area equal to 810π (unit²)