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Solve the simultaneous equation, 5x=2y+1 2x-3y+4+0

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Hello,

I suppose the 2th equation is 2x-3y+4=0

5x-2y=1 ........|*2 | *3
2x-3y=-4....... |*(-5) | *-2
==> -4y+15y=2+20==>11y=22==>y=2
and 15x-4x=3+8 ==>11x=11 ==>x=1
Proof:

5*1=? 2*2+1 yes
2*1-3*2+4=? 0 yes (linear combinaison method)
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