212,711 views
2 votes
2 votes
I need to solve for x and how many three-digit numbers is the above inequality true for

I need to solve for x and how many three-digit numbers is the above inequality true-example-1
User Eigir
by
2.7k points

1 Answer

22 votes
22 votes

Given:


(x)/(3)+(x)/(6)\ge(x)/(4)+230

Required:

we have to calculate the above equation for the value of x.

Step-by-step explanation:

First of all we find common denominator


\begin{gathered} (2x+x)/(6)\ge(x)/(4)+230 \\ \\ combine\text{ like terms} \\ (3x)/(6)\ge(x)/(4)+230 \end{gathered}
\begin{gathered} cancel\text{ terms that are in both numenator and denomenator} \\ (x)/(2)\ge(x)/(4)+230 \\ find\text{ common denominator} \\ (x)/(2)\ge(x)/(4)+\frac{4.230}{4\text{ }} \\ \\ (x)/(2)\ge(x+4.230)/(4) \\ \end{gathered}
\begin{gathered} multiply\text{ the numbers} \\ (x)/(2)\ge(x+920)/(4) \\ multiply\text{ all terms by the same value to eliminate fraction denominator.} \\ 4.(x)/(2)\ge4.(x+920)/(4) \\ cancel\text{ multiplies terms that are in denominator} \\ 2x\ge x+920 \\ subtract\text{ x from both the sides} \\ x\ge920 \end{gathered}

Required answer:


x\ge920

User Nonremovable
by
3.3k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.