The quadratic equation y=2x^2-px+6 has equal roots. Find the possible values of p.

asked Feb 13, 2015 139k views

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$\Delta=0\\ \Delta=(-p)^2-4\cdot2\cdot6=p^2-48\\ p^2-48=0\\ p^2=48\\ p=√(48) \vee p=-√(48)\\ p=4\sqrt3 \vee p=-4\sqrt3$

Viren Rajput answered Feb 18, 2015

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