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The two squares x and y are mathematically similar. The areas of x and y are 17cm squared and 272cm squared, respectively. The length of x is 5cm. Fine the corresponding length of y.
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The two squares x and y are mathematically similar. The areas of x and y are 17cm squared and 272cm squared, respectively. The length of x is 5cm. Fine the corresponding length of y.

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I would set this up as a a proportion:

(17cm)/(5cm) ·
(272cm)/(x)
17x = 1360
x = 20 cm
User Paul Frank Allan
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