Question

Factor completely 14bx2 − 7x3 − 4b + 2x.

(2b + x)(7x2 + 2)

(2b − x)(7x2 − 2)

(2b + x)(7x2 − 2)

Prime

Answer 1

hello,

14bx²-7x^3-4b+2x= -7x^3+14bx²+2x-4b
=-7x²(x-2)+2(x-2b)
=(x-2b)(-7x²+2)
=(2b-x)(7x²-2)

answer 2

Answer 2

`(2b-x)(7x^2-2)`

Explanation:

We have to factor the expression
`14bx^2-7x^3-4b+2x`

We apply the method of grouping to factor it.

Make groups

`(14bx^2-7x^3)+(-4b+2x)`

Take GCF

`7x^2(2b-x)-2(2b+x)`

Finally, factored out the common factor

`(2b-x)(7x^2-2)`

The factored form of the given expression is

`(2b-x)(7x^2-2)`