Question

Factor completely 4x3 + 28x2 + 7x + 49.

(x − 7)(4x2 + 7)

(x − 7)(4x2 − 7)

(x + 7)(4x2 + 7)

(x + 7)(4x2 − 7)

Answer 1

Please fallow the steps it will help you

Step1: 4x^3 + 28x^2 + 7x + 49

Step 2: 4x^2(x+7) + 7(x+7)

Step 3: (4x^2+7)(x+7)

Step 4: (x+7)(4x^2+7)
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Hope that helped!

Answer 2

`(x+7)(4x^2+7)`

Explanation:

The given expression is
`4x^3+28x^2+7x+49`

We can factor it by grouping method.

So, group the terms as shown below

`(4x^3+28x^2)+(7x+49)`

Take GCF from each group

`4x^2(x+7)+7(x+7)`

Factored out the common term (x+7)

`(x+7)(4x^2+7)`

Thus, the factored form is
`(x+7)(4x^2+7)`