Question

Factor completely 10xy + 3y + 20ax + 6a.

(10x − 3)(y − 2a)

(10x − 3)(y + 2a)

(10x + 3)(y + 2a)

(10x + 3)(y − 2a)

Answer 1

10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)=
(y+2a)(10x+3)

Answer 2

Option 3 is correct.

Explanation:

The given expression is

`10xy+3y+20ax+6a`

This expression can be written as

`(10xy+3y)+(20ax+6a)`

Take out the common factors from each parenthesis.

`y(10x+3)+2a(10x+3)`

Now, take out the common factor (10x+3).

`(10x+3)(y+2a)`

Therefore option 3 is correct.