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4 votes
Factor completely 10xy + 3y + 20ax + 6a.

(10x − 3)(y − 2a)

(10x − 3)(y + 2a)

(10x + 3)(y + 2a)

(10x + 3)(y − 2a)

User Eglease
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8.7k points

2 Answers

2 votes
10 xy + 3y + 20 ax + 6a = y(10x+3) + a(20x+6) = y(10x+3)+2a(10x+6)=
(y+2a)(10x+3)
User SImon Haddad
by
9.2k points
3 votes

Answer:

Option 3 is correct.

Explanation:

The given expression is


10xy+3y+20ax+6a

This expression can be written as


(10xy+3y)+(20ax+6a)

Take out the common factors from each parenthesis.


y(10x+3)+2a(10x+3)

Now, take out the common factor (10x+3).


(10x+3)(y+2a)

Therefore option 3 is correct.

User Sergio Ivanuzzo
by
7.9k points