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Factor completely 3x2 + 9x − 3.

3(x2 + 3)

3(x2 + 3x − 1)

3x(x2 + 3x − 1)

Prime

User Tomas By
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2 Answers

3 votes
Factor completely: 3x2 + 9x − 3

3x2 + 9x − 3 (a 3 can be divided from each number)
3(x2+3x-1)

can x2+3x-1 be factored out anymore? no

3(x2+3x-1) is the answer

User BnMcGn
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7.8k points
6 votes

Answer:

Option (2) is correct choice.

Explanation:

Given polynomial
3x^2+9x-3

We have factorize the given polynomial and choose the correct from options given.

Factor are the smallest forms a given number is broken such that the product of factors gives back the number we factorized.

Here,
3x^2+9x-3

First taking 3 common from whole expression.


3x^2+9x-3=3(x^2+3x-1)

Thus, option (2) is correct choice.



User Top Sekret
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8.5k points