Question

when you reverse the digits in a certain two-diget number you increase it value by 27. What is the number if the sum of its digits is 5

Answer 1

14 or 41

41 - 14 = 37

4+1 = 5

Answer 2

The number is = 10x+y
if reverse the digits, the number is: 10y+x
The sum fo its digits is = x+y=5
I suggest this system of equations:
(10y+x)-(10x+y)=27 ⇒9y-9x=27
x+y=5
We can solve this system of equations by equaliztion method
x=5-y

9y-9(5-y)=27
9y-45+9y=27
18y=27+45
18y=72
y=72/18
y=4

x=5-y
x=5-4=1

The number is: 10x+y=10(1)+4=14

Answer: the number is 14