Question

What is the perimeter of triangle ABC with vertices A(-1,-2), B(2,-6), and C(-3,-6)?

Answer 1

find the distance between the points and that is perimiter

find
A to B
B to C
C to A
we need the distance formula
D=
`\sqrt{(x2-x1)^(2)+(y2-y1)^(2)}`
where D is the distance between points (x1,y1) and (x2,y2)

A to B
(-1,-2) to (2,-6)
D=
`\sqrt{(2-(-1))^(2)+(-6-(-2))^(2)}`=5

B to C
(2,-6) to (-3,-6)
since the y value stayed the same, find the distance betwen the x values
2 to -3 is distance of 5

C to A
(-3,-6) to (-1,-2)
D=
`\sqrt{(-1-(-3))^(2)+(-2-(-6))^(2)}`=2√5

add everybody

5+5+2√5=10+2√5 units