Question

Evaluate x^0 y^-4 for x = 2 and y = 3.

Answer 1

We have to evaluate the expression:

`x^0y^(-4)=1\cdot y^(-4)=(1)/(y^4)`

for x=2 and y=3.

The value of x is elevated to the exponent 0 so the value of x^0 is always 1 for any value of x.

Then, we replace y with 3 and calculate:

`x^0y^(-4)=(1)/(y^4)=(1)/(3^4)=(1)/(81)`

Answer: the value of the expression for x=2 and y=3 is 1/81.