Question

Answer and maybe an explanation.Thanks in advance.

Answer 1

inverses

solve for x
replace x with f inverse
replace y with x



so
first minus 2 both sides
y-2=√(2x-3)
square both sides
y^2-4y+4=2x-3
add 3 to both sides
y^2-4y+7=2x
divide both sides y 2
(y^2-4y+7)/2=x

x turns to f inverse and y turns to x


f(x)⁻¹=
`(x^(2)-4x+7)/(2)`


looks like they didn't want to expand the binomial

y=
`\frac{(x-2)^(2)}+3}{2}`
answer si A