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What is the least number that has 4 odd factors that are all the same? Each factor is greater than 1 and can have only 1 itself as factors

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I'm not quite sure what you mean.
the factors can't be 1.
the factors have to be odd.
they have to be the same.
offhand i would say 3*3*3*3 would be equal to 9*9 = 81.
the number 81 has 4 odd factors that are all the same.
can't be 1 because 1 doesn't counts as a factor.
a prime number has 2 factors.
1 and itself.
every number has a factor of 1 and itself.

User Khanh Pham
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