Question

Plz help

The quadratic equation 3x^2+6x-6=0 an be rewritten as the equation below, where p and q are constants.
(x-p)^2=q
what is the value of p?

Answer 1

p=-1

Explanation:

3x^2+6x-6=0

Add 6 on both sides

3x^2+6x=6

Divide through by 3

x^2+2x=2

Complete the square on the right side

If a quadratic equation is given by

ax^2+bx+c=0

then c=b/2

x^2+2x=2

c=2/2=1

Adding 1 on both sides

x^2+2x+1=2+1

x^2+x+x+1=3

Combining

x(x+1)+1(x+1)=3

(x+1)(x+1)=3

(x+1)^2=3

p=-1