How many possible values are there for x in the equation?X2 = 36/81

Kyleobrien asked Jan 5, 2023

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36 votes

Kyleobrien asked Jan 5, 2023

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14 votes

It is given that

$\begin{gathered} x^2=(36)/(81) \\ x=\sqrt[]{(36)/(81)} \\ x=\pm(6)/(9) \end{gathered}$

So there are two possible values of x .

Hence the correct option is b) two values

Arman Sharma answered Jan 10, 2023

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