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What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
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Jun 11, 2017
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What is the sum of the geometric series 2^0 + 2^1 + 2^2 + 2^3 + 2^3 + 2^4 + … + 2^9?
Mathematics
high-school
Secador De Pelo
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so this one you don't multiply the base by the exponent. in this case its 2 times two how ever many time the exponent says.
2^0= 2
2^1= 2
2^2=4
2^3= 8
2^4=16
2^5=32
2^6=64
2^7=128
2^8=256
2^9=512
So then you add all them up
2+2+4+8+16+32+64+128+256+512= 1024
so there is your answer 1024
Agung Setiawan
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Jun 12, 2017
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Agung Setiawan
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sum is
r=common ratio
a1=first term
it looks like 2^0=1 is the first term aka a1
it goes to the 9th term (2^9)
sub
ECorke
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Jun 16, 2017
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ECorke
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