Question

2) Write the equation of the line that passes through the point (-3, -1) with a slope of -2/3.

A. y = (-⅔)x - 8
B. y = (-⅔)x - 1
C. y = (-⅔)x - 11/3
D. y = (-⅔)x - 3

Answer 1

y=mx+b
slope=m
yint=b
we are given
slope=-2/3
point=(-3,-1)

y=-2/3x+b
input point -3,-
x=-3
y=-1
find b
-1=-2/3(-3)+b
-1=2+b
minus 3
-3=b

y=-2/3x-3


answer is D