The vertices of the translated triangle are:
C. A'(–6, –1), B'(–5, –7), and C'(1, –4)
How to find the coordinates after translation?
The original coordinates of the triangle are:
A(-3, 4)
B(-2, -2)
C(4, 1)
A translation to the right by 3 units and down by 5 units gives:
A'(-3 - 3, 4 - 5)
B'(-2 - 3, -2 - 5)
C'(4 - 3, 1 - 5)
= A'(-6, -1)
B'(-5, -7)
C'(1, -4)