Answer:
The equation of the image of A after a dilation with a scale factor of 2 will be:
Explanation:
Some background Knowledge about dilation.
We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.
- If the scale factor > 1, the image is enlarged
- If the scale factor is between 0 and 1, it gets shrunk
- If the scale factor = 1, the object and the image are congruent
Rule to calculate the dilation by a scale factor 2 centered at the origin
P(x, y) → P'(2x, 2y)
Here, P'(2x, 2y) is the image of P(x, y).
- It means the coordinates of the image can be determined by multiplying the coordinates of the original point by 2.
Now, let us solve our case:
Given the points
Let say the points are X(-3, -4) and Y(-6, -5)
Rule to calculate the dilation by a scale factor 2 centered at the origin
P(x, y) → P'(2x, 2y)
so
X(-3, -4) → X' (2(-3), 2(-4)) → X'(-6, -8)
Y(-6, -5) → Y' (2(-6), 2(-5)) → Y'(-12, -10)
Thus, after the dilation scale of factor 2, now the image line will through the points X'(-6, -8) and Y'(-12, -10)
so we have the points of the image line
Determining the slope between X'(-6, -8) and Y'(-12, -10)



The slope-intercept form of the line equation
y = mx+b
where
now substituting m = 1/3 and (-6, -8) in the slope-intercept form of the line equation



Add 3 to both sides

Simplify

now substituting b = -6 and m = 1/3 in the slope-intercept form of line equation



Therefore, the equation of the image of A after a dilation with a scale factor of 2 will be: