Question

Graph the line that has a slope of 1/5 and includes the point (0,1).

Answer 1

Given:

`\text{Slope(m)}=(1)/(5)\text{ ; Point (0,1)}`

Equation of line is

`y-y_1=m(x-x_1)`
`\begin{gathered} y-1=(1)/(5)(x-0) \\ 5y-5=x \\ x-5y+5=0 \end{gathered}`

Equation can be written as

`y=(x+5)/(5)`

x=-10,

`\begin{gathered} y=(-10+5)/(5) \\ y=(-5)/(5) \\ y=-1 \end{gathered}`

x=-5,

`\begin{gathered} y=(-5+5)/(5) \\ y=0 \end{gathered}`

x=0

`\begin{gathered} y=(5)/(5) \\ y=1 \end{gathered}`

x=5

`\begin{gathered} y=(5+5)/(5) \\ y=2 \end{gathered}`

x=10

`\begin{gathered} y=(10+5)/(2) \\ y=3 \end{gathered}`

Plot the points on the graph

`(-10,-1),(-5,0),(0,1),(5,2),(10,3)`