Answer:
We conclude that the linear equation in slope-intercept form with a slope of 5 and point (2, -20) is:
Explanation:
The slope-intercept form of the line equation
where
Given
The slope m = 5
The point (2, -20)
now substitute (x, y) = (2, -20) and m = 5 in the slope-intercept form of the line equation
y = mx+b
-20 = 5(2) + b
10 + b = -20
subtracting 10 from both sides
10 + b - 10 = -20 - 10
b = -30
Thus, the y-intercept b = -30
so substituting b = -30 and m = 5 in the slope-intercept form of the line equation
y = mx+b
y = 5x + (-30)
y = 5x - 30
Therefore, the linear equation in slope-intercept form with a slope of 5 and point (2, -20) is: