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The square of a number is equal to 10 less than 7 times that number. What are the two possible solutions? Which of the following equations is used in the process of solving this problem?

User Claudy
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2 Answers

3 votes

Answer:


x^2+7x-10=0

Explanation:

The two possible solutions are 2 and 5. But the equation used in the process of solving and finding this problem, is x^2 + 7x - 10 = 0 or
x^2+7x-10=0.

Hope I helped :)

User Maxym
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Solution: Let x be the number. Transform into equation form: x^2 = 10 - 7x. x^2 + 7x - 10 = 0 Factor: (x-5)(x-2)=0; Thus, x = 5 or x = 2. The two possible solution is 5 and 2.
User Nvuono
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