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What is the vertex f(x)= 5x^2+20x-16
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Jun 3, 2017
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What is the vertex f(x)= 5x^2+20x-16
Mathematics
middle-school
Enioluwa Segun
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Enioluwa Segun
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f(x) = 5x² + 20x - 16
y = 5(x² + 4x) - 16
y + 16 = 5(x² + 4x + __)
perfect square:
x² ⇒ x * x
4x ⇒ 2*2x
2² = 4
y + 16 + 4 = 5(x² + 4x + 4)
y + 20 = 5(x+2)²
(x+2)² ⇒ (x+2)(x+2) = x(x+2) + 2(x+2) = x² + 2x + 2x + 4 = x² + 4x + 4
y = 5(x+2)² - 20
Christophe Vidal
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Jun 9, 2017
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Christophe Vidal
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