A total of $27,000 was invested; part of it at 10% and part of it at 12%. The total yield was $2990. How much was invested at each rate?
Let
x -----> amount invested at 10%
(27,000-x) -----> amount invested at 12%
we have that
0.10(x)+0.12(27,000-x)=2990 ------> equation A
solve for x
0.10x+3,240-0.12x=2,990
0.12x-0.10x=3,240-2,990
0.02x=250
x=$12,500
so
27,000-x=27,000-12,500=$14,500
therefore
amount invested at 10% ----> $12,500
amount invested at 12% -----> $14,500