Question

Which of the following are solutions to the equation below?

check all that apply.

x^2+4x+4=6

A. x=-2+√6

B. x=2

C. x=-2-√6

D. x=0

E. x=2-√6

F. x=2+√6

Answer 1

solve
set to zero by minusing 6 both sides

x^2+4x-2=0

we can't factor

ok so use quadratic formula
ax^2+bx+c=0
x=
`\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}`

a=1
b=4
c=-2

x=
`\frac{-4+/- \sqrt{4^(2)-4(1)(-2)} }{2(1)}`
x=
`(-4+/- √(16+8) )/(2)`
x=
`(-4+/- √(24) )/(2)`
x=
`(-4+/- 2√(6) )/(2)`
x=
`-2+/- √(6)`


x=
`-2+ √(6)` or
`-2- √(6)`

answer is A and C