Question

What are the solutions to the equation?22 5x 12-0

Answer 1

2x²-5x-12=0

Factor left side of the equation

(2x+3)(x-4)=0

Set factors equal to 0

2x+3=0 or x-4=0

x=-3/2 or x=4

I hope that's help !

Answer 2

the equestion is
2x^2-5x-12=0
we can either try to factor, or use quadratic formula
trial and errot
(x-4)(2x+3)=0
set to zero
x-4=0
x=4
2x+3=0
2x=-3
x=-3/2

x=-3/2 or 4