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What is the expanded form of 3x(x+3)^2?

User Carbonizer
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pemdas
exponents first
(x+3)^2=(x+3)(x+3)=x^2+3x+3x+9=x^2+6x+9
multiply
3x(x^2+6x+9)
3x^3+18x^2+27x
User ArturFH
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