Question

Use any order, any grouping to write an equivalent expression: 3(2x) + 4y(5) + (4 x 2 x z)

Answer 1

We conclude that the equivalent expression is:

`3\left(2x\right)+4y\left(5\right)+\left(4* \:2z\right)=6x+20y+8z`

Explanation:

Given the expression

`3\left(2x\right)+4y\left(5\right)+\left(4* \:2z\right)`

Remove parentheses: (a) = a

`=3* \:2x+4* \:5y+4* \:2z`

Multiply the numbers: 3 × 2 = 6

`=6x+4* \:5y+4* \:2z`

Multiply the numbers: 4 × 5 = 20

`=6x+20y+4* \:2z`

Multiply the numbers: 4 × 2 = 8

`=6x+20y+8z`

Thus, we conclude that the equivalent expression is:

`3\left(2x\right)+4y\left(5\right)+\left(4* \:2z\right)=6x+20y+8z`