Question

If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.

2st

2 over the quantity s times t

the quantity of 2 times s all over t

t over the quantity 2 times s

Answer 1

`(2s)/(t)`

Explanation:

Answer 2

Given:
Area = 16s²t
Length = 8st²
Width = ?

Width = Area / Length
Width = 16s²t / 8st²
Width = 2s/t ⇒ the quantity of 2 times s all over t.