Question

If h(x) = 3x − 1 and j(x) = −2x, solve h[j(2)] and select the correct answer below.

−11
11
−13
13

Answer 1

h(x) = 3x - 1
j(x) = -2x

h[j(2)] ⇒ j(2) = -2(2) ⇒ j(2) = -4

h(-4) = 3(-4) - 1
h(-4) = -12 - 1
h(-4) = -13

h[j(2)] = -13

Answer 2

Option 3rd is correct.

the value of h[j(2)] is, -13

Explanation:

Given the functions:

`h(x) = 3x-1`

`j(x) = -2x`

We have to find the value of h[j(2)]

`h[j(x)] = h[-2x]`

Replace x from -2x in h(x) we have;

`h[-2x] = 3(-2x)-1 = -6x -1`

⇒
`h[j(x)] = -6x-1`

Substitute the value of x = 2 we get;

`h[j(2)] = -6(2)-1 = -12-1 = -13`

Therefore, the value of h[j(2)] is, -13