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Terry has number cube with sides labeled 1 through 6. He rolls the number cube twice. What is the probability that the sum of the two rolls is a prime number or at least one of the rolls is a 3? Explain your reasoning

User Robbyt
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1 Answer

4 votes

Sum of the points ot the two rolls

Roll 1 1 2 3 4 5 6
Roll 2
1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

Prime results:
2: once, 1
3: twice, 2
5: four times, 4
7: six times, 6
11: twice, 2

The easiest way is to count all the results in which none of the rolls was a three and the sum of the two rolls was not a prime number: it is 14 results.

Now subtract those 14 results from the 36 possible outcomes, the difference is the number of results in which either the sum of the rolls is a prime or at least one of the numbers is three: 36 – 14 = 22

Probability = positive events / total events

Probability: 22/36 = 11/18

Please, let me know if my explanation was clear enough.


User Jens Ehrlich
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7.1k points
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