How many grams of NH3 are in 3.011x10^23 molecules of NH3

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asked Oct 23, 2017 29.2k views

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Cfrag · Answer 1 · 2017-10-27T23:00:25+0000

(3.011×10^23mlc NH3)×((1 Mol NH3)/(6.02x10^23mlc NH3))×(17 g NH3/1 Mol NH3). Multiply it all out and you get 8.503 g NH3 rounded to the correct number of sig digs.

How many grams of NH3 are in 3.011x10^23 molecules of NH3

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