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The zeros of the function f (x)=(x+2)^2-25

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diffrence of 2 perfect squraes
a^2-b^2=(a-b)(a+b)

(x+2)^2-(5)^2=(x+2-5)(x+2+5)=(x-3)(x+7)

set to zero
x-3=0
x=3

x+7=0
x=-7

zeoes are x=3 and -7
User Zhigang
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