Question

Line k's equation is y =8/7 x - 3 Line l is perpendicular to line k and passes through the point (2,-15/4). Find an equation for line ( in both point-slope form and slope-intercept for I An equation for l in point-slope form is. An equation for l in slope-intercept form is

Answer 1

The equation for k is,

`y=(8)/(7)x-3`

Here slope is 8/7..

Since, line I is perpendicular to k, the slope of the line I is, -7/8.

The general line equation is,

`y=mx+b`

Here, m is the slope and b is the y intercept.

As the line passes through the points (2, -15/4), we have,

`\begin{gathered} -(15)/(4)=-(7)/(8)*2+b \\ -(15)/(4)=-(7)/(4)+b \\ b=-(15)/(4)+(7)/(4)=-(8)/(4)=-2 \end{gathered}`

Thus, the equations are,

`y=-(7)/(8)x-2`

The point slope form is,

`y+(15)/(4)=-(7)/(8)(x-2)`