Question

What is the minimum value for g(x) = x^2 – 10x + 16?

would it be 2?

Answer 1

vertex aka mn or max value when you have
f(x)=ax^2+bx+c
vertex=-b/2a

a=1
b=-10
-b/2a
-(-10)/2(1)=10/2 =5

min value is 5
sub 5 for x
5^2-10*5+16
25-50+16
-9
min point is (5,-9)