A group of 50 students took an exam.The probability of choosing a student who failed from the group is 1/10.If two students are chosen at random from the group, what is the probability for both of them to pass the exam?
Given the probability of failure (event F) = 1/10 = 0.1
Step-by-step:
Accordingly, the probability of success = 1 - 0.1 = 0.9
So, the probability of getting both the sample drawn to be have passed the exam = 2C2*(0.9)^2(0.1)^0 = 1*0.81*1 = 0.81
Alternately
Probability of failure = 0.1 => 50*0.1 = 5 cases of failure
Accordingly number of students who are likely to pass = 50 - 5 = 45
So, the required probability 45C2/50C2 = (45*44/1*2)/50*49/1*2
= 45*44/50*49 =1980/2450 = 0.808 or 0.81