Question

I’ve tried calculating it on my own but what I get is no where near the answers?

Answer 1

Given data:

It is clear from the given image that the triangle is a right angle triangle.

Right angle is at

In a triangle right angle is at C so the hypotenues is always opposite to the right angle that is AB.

Finding the angle B, use trigonometric identity

`\tan \theta=(perpendicular)/(base)`

Here, perpendicular is AC because it is always opposite to the angle which we need to find.

AC = 9

Base, BC = 10

Therefore , we have

`\tan \theta=(9)/(10)`
`\begin{gathered} \theta=\tan ^(-1)(0.9) \\ \theta=41.98 \\ \theta\approx42^(\circ) \end{gathered}`

Thus, the correct option is (A) that is 42 degreeD