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(8b2+6b-1) (8b2-8b+7)
asked
Apr 2, 2017
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4
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(8b2+6b-1) (8b2-8b+7)
Mathematics
high-school
Geoffreyd
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Geoffreyd
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1
Answer
4
votes
=(
8
b2
+
6b
+
−1
)
(
8
b2
+
−
8b
+7
)
=
(8b2)(8b2)+(8b2)(−8b)+(8b2)(7)+(6b)(8b2)+(6b)(−8b)+(6b)(7)+(−1)(8b2)+(−1)(−8b)+(−1)(7)
=
64b4−64b3+56b2+48b3−48b2+42b−8b2+8b−7
Answer:
=
64b4−16b3+50b−7
Yaniv Shaked
answered
Apr 8, 2017
by
Yaniv Shaked
8.4k
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