Question

Find -x + 10 less than 0.

0
-x + 10
x - 10

Answer 1

`-x + 10 \ \textless \ 0`

Transposing the inequation gives:

`-x \ \textless \ -10`

Since we want to get rid of the negatives on both sides, we must flip the sign:

`x \ \textgreater \ 10`

If you transpose the equation to make RHS be 0:

`x - 10 \ \textgreater \ 0`
That seems to satisfy  x - 10 (could be wrong though...)

But I'm not exactly clear on what you want as the options above don't seem to give that much context :I