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What are the solutions to the equation x^2-8x=24

User Gopichand
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x^(2) - 8x = 24

Transposing the equation to give zero on the RHS:

x^(2) - 8x - 24 = 0

Since we can't factorise it directly, we must complete the square to yield any solutions:

x^(2) - 8x + ( (8)/(2))^2 - ((8)/(2))^2 - 24 = 0

(x^(2) - 8x + 16) - 16 - 24 = 0

(x-4)^2 - 40 = 0

(x-4)^2 = 40

x-4 = +/- √(40) ––> because square rooting yields a positive and negative solution.
x = 4 +/-
√(40)
x = 4 +/-
2 √(10)

Correct me if I'm wrong anyone.
User Eadam
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