Question

Jogger A has a mass m and a speed v, jogger B has a mass m/2 and a speed 3v, jogger C has a mass 3m and a speed v/2, and jogger D has a mass 4m and a speed v/2. Rank the joggers in order of increasing kinetic energy. Indicate ties when appropriate. Show your work.

Answer 1

Answer: B>A=D>C

Step-by-step explanation:

Kinetic Energy is the product of mass and square of the velocity

For Jogger A

`K.E._a=(1)/(2)mv^2`

For Jogger B

`K.E._b=(1)/(2)*(m)/(2)*(3v)^2=(9)/(4)mv^2\\K.E._b=2.25mv^2`

For Jogger C

`K.E._c=(1)/(2)*3m*((v)/(2))^2=(3)/(8)mv^2\\K.E._c=0.375mv^2`

For Jogger D

`K.E._d=(1)/(2)*4m*((v)/(2))^2=(1)/(2)mv^2`

Kinetic Energy of Joggers in increasing order

B>A=D>C