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The length of a rectangle is 7 yd less than three times the width, and the area of the rectangle is 66 yd ^2. Find the dimensions of the rectangle

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Final answer:

To find the dimensions of the rectangle with an area of 66 square yards and a length that is 7 yards less than three times its width, we set up and solve the equation w(3w - 7) = 66 for the width (w), then calculate the length using the expression 3w - 7.

Step-by-step explanation:

The student is asking to find the dimensions of a rectangle where the length is 7 yards less than three times the width, and the area is 66 square yards. To solve this, we can set up an equation based on the area of a rectangle, which is length times width. Let's denote the width as w and the length as 3w - 7. The equation for the area of the rectangle is:

w(3w - 7) = 66

Solving for w, we get:


3w^2 - 7w - 66 = 0

Factoring this quadratic equation, we find values of w. Since we're looking for positive dimensions, we'll take the positive value of w that satisfies the area. After finding the width, we can easily calculate the length by plugging the width into the length expression 3w - 7.

Thus, the dimensions of the rectangle would be the width w and the length 3w - 7 yards.

User Vinit Dabhi
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x-\ width\\ (3x-7)\ -\ length\\\\ Formula \ for\ area\ of\ rectangle:\\Area=2length+2width\\\\ 66=2x+2(3x-7)\\ 66=2x+6x-14\\ 66=8x-14\ \ \ |Add\ 14\\ 80=8x\ \ \ |Divide\ by\ 8\\ x=10\\ 3x-7=3*10-7=30-7=23\\\\Dimensions:\\ length: 23yd\\ width:10yd.
User Lalit Kumar B
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