Question

Use Descartes rule of signs to complete the chart with the possibilities for the nature of the roots of the equations:A) x^3 - x^2 + 4x -6 =0

Answer 1

Given:

`x^3-x^2+4x-6=0`

We will use Descartes's rule of signs to identify the nature of the roots of the equation.

The coefficients will be as follows:

+1, -1, +4, -6

As shown therearea 3 changes from (+) to (-) or reverse

So, the number of positive real roots = 2 or 1