Question

What is the rate of change for the interval between 0 and 2 for the quadratic equation as f(x) = 2x2 + x – 3 represented in the table? (The table has this: Left side X and the options going down are -2, -1, 0, 1, 2. Right Side f(x) and the options going down are 3, -2, -3, 0, 7) THE ANSWER OPTIONS ARE: 1/5, 4, 5, 10

Answer 1

(C) 5

Explanation:

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Answer 2

By definition the rate of change of a function is given by:

`AVR = (f(x2) - f(x1))/(x2 - x1)`
For the interval [0, 2] We have to make use of the table:

`f(0)=-3 f(2)=7`
Therefore, substituting values in the given expression we have that the average change of rate is given by:

`AVR = (7-(-3))/(2-0)`
Rewriting we have:

`AVR = (7+3)/(2-0)`

`AVR = (10)/(2)`

`AVR = 5`
Answer:
the rate of change for the interval between 0 and 2 is:

`AVR = 5`