Question

A triangle has height 4 ft and area 32 ft2. What is the lenght of the base?

Answer 1

`Formula\ for\ area\ of\ triangle:\\\\ Area=(1)/(2)base*height\\\\ 32=(1)/(2)*4*base\\\\ 32=2base\ \ \ |Divide\ by\ 2\\\\ base=16ft\\\\ Length\ of\ base\ is\ equal\ to\ 16ft.`

Answer 2

`A=32ft^2 \\\\ A=(b*h)/(2) \\\\ (b*4)/(2)=32 \\\\ b=(2*32)/(4) \\\\ b=2*8 \\\\ \boxed{b=16ft}`