one way is trial and error
equation of exonential is
y=a(b^x)
lets try some stuff
one way is trial and error
after 20 minutes we come up with y=3(2^x)
another way is recognizing that this is a sequence

a1=6, cool
sub
a4=48


dividie everybody by 6

cube root
2=r
therefor
equation is
f(x)=3(2^x) or y=3(2^x)