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Exponential Form

3.log 1/4 1=0
4.log 1/2 32= -5
Evaluate the logarithm
6. log27 3=
8. log 1/4 256=
9. log 10 .001=
10. log 64 2=

2 Answers

5 votes
loga n=z ⇔a^z=n

Therefore:
3)log 1/4 1=0 ⇔(1/4)⁰=1
4)log 1/2 32 -5 ⇔(1/2)⁻⁵=2⁵=32

6)
log 27 3=n ⇔ 27^n=3
27=3³
(3³)^n=3 ⇒n=1/3 (3³)¹/³=3³/³=3¹=3

Answer: log 27 3=1/3

7)
log1/4 256=n ⇔(1/4)^n=256
256=2⁸=4⁴
(1/4)^n=4⁴ ⇒n=-4 [ (1/4)⁻⁴=4⁴=256 ]

Answer: log1/4 256=-4

9)
log 10 0.001=n ⇔ 10^n=0.001
0.001=10⁻³
10^n=10⁻³ ⇒n=-3

answer: log 10 0.001=-3

10)
log 64 2=n ⇔64^n=2
64=2⁶
(2⁶)^n=2 ⇒2(⁶n)=2¹ ⇒ 6n=1 ⇒ n=1/6

answer: log 64 2= 1/6

User MalloyDelacroix
by
8.1k points
5 votes
6. 1/3
8. -4
9. -3
10. 1/6
User Ryan Bosinger
by
8.1k points

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